In this problem, we see that we have an atom presented to us. It tells us that it only has one electron in its valence shell. And we're seeing the set of quantum numbers for that electron. So what information does the number 3, 0, 0, plus one half tell us? Well, the n is 3. And the, and that's when we're in the third shell. And when when the l is equal to 0, that is an s subshell. So we have a electron in the 3s subshell, spinning a certain way. Well there's only one orbital there. Let's look at a periodic table. So if we count down one, two, three, and it has only one electron valence shell, we must be dealing with sodium, and it has 11 electrons. So the element has to be sodium. And if we were to do the electron configuration and account for all 11 electrons, we would start at the lowest level, which is 1s. Put two electrons there. And then we go to the 2s and put two electrons there. Then we would go to the 2p and there's three orbitals in the 2p. So we would go and we would fill it up as so, and that uses ten of the electrons, and we go to the next level, which is a 3s. And we would put that one electron there. So this electron is the last final electron that has that set of quantum numbers, and it's a sodium atom and there's its electron, not its configuration, but its orbital diagram. I could also write its electron configuration. It would be 1s2, 2s2, 2p6 and 3s1.