Okay, now let's consider the another example. Say x ′ equal to, okay? [- 1 5] [-1 1] * X. And + [- sine t] and [2 cos t], right? And initial condition will be X(o) = [0- 1/3], okay? So this initial very problem, okay? That is equal to, let's call this matrix the coefficient matrix, A. AX plus, rely to this non-homogeneous term, okay? As [-1 0] sine T and + [ 0 2], and cos T. So it's a combination of the sin function and the cosine function, right? Okay, again, we know that. Okay, general solution X is equal to complementary solution, Xc, plus particular solution Xp, right? To find this complementary solution, just to look at the Eigen values. And the corresponding Eigen vectors of this corresponding the coefficient matrix, A, right? Then it's easy to find that. Okay, the A has okay, Eigen values, +_2i. And the corresponding Eigen vectors, okay? Corresponding Eigen vectors[1 1] +-i [-2 0], okay? Okay, and that means, okay? We get the complementary solution, right? Easy to write down the complementary solution. That is equal to C1, okay? Cos 2t, and + 2 sin 2t, okay? And the cos 2t, and + C2, okay? And the sin 2t -2 cos 2t, and the sin 2t, okay? That's a complementary solution, right? Now, it's time to make the reasonable guess for the particular solution, Xp, right? Okay, what should the Xp, the top of the Xp, right? Just to look at this non-homogeneous term. This is a linear combination of sin T. And the cos T. So, okay. It's reasonable to make a guess for the particular solution. Say Xp=[a1 a2], a non-coefficient times sin T + another non-coefficient, [B1 B2] * cos T, okay? That's a guess, right? Guess for the particular solution, okay? In fact it works well, okay? Plug in this Xp, okay? Into this system of equation, right? Non-homogeneous system of equation. You can easily confirm that actually the Xp = 1/3, okay? Sin t, and + 3 cos t, okay? And -1/3 sin t, okay? Plus 2/3 cos t, okay? That's a particular solution you can get from this guess, okay? So that means if you already have the general solution X. X is equal to, right? General solution, X is equal to, right? This complementary solution part plus this particular solution, okay? 1/3 sin t + 3 = sin t, okay? And the -1/3 sin t = 2/3 cos t, okay? That's the general solution of the original problem, okay? Now, using this initial condition, okay? Using this initial condition, okay? So, put T = 0, okay? Put T = 0 in this general solution. And = [0 -1/3], okay? Using this, okay? So, using this initial condition X(0) = [0 -1/3], okay? Plugging this, then you will get C1 = -1. And the C3 = 1, okay? So finally the solution will be, right? I skipped the simple computation involved, right? That is equal to [- sin 2t- 3 cos 2t + 1/3 t + 3 cos t, okay? And [sin 2t- cos 2t -1/3 sin t + 2/3 cos t], right? That's the solution to the given initial value problem, okay? I will discuss this with one more example, okay? One more example by which, okay? I'd like to discuss some minor difference of the method of undetermined coefficients for the single non-homogeneous linear differential equation. And the systems non-homogeneous system of differential equations, right? One minor difference in making a guess for the type of the particular solution Xp, okay? Let's first consider the following motivating example from the single non-homogeneous linear differential equation, okay? I will consider the following problem. Y ′ ′- y ′- 2y = 3e-t -2, okay? Okay, let's be back to the situation, okay? For the differential equations, the part one, okay? Non-homogeneous single linear second order differential equation with constant co-efficient, right? As we said, a general solution is equal to complementary solution plus particular solution, okay? Complementary solution is a general solution of corresponding homogeneous problem. This is a very simple constant coefficients homogeneous second order differential equation. Its characteristic equation will be, can you remind, I -r -2. That is equal to (r-2). And (r +1 ) = 0. So that we have two character. Say, r1 =2. And r2= -1, right? What does that mean then? Okay, the general solution of this homogeneous problem. In other words, complementary solution will be, c1 e2d- t + c2 e2 2t, right? That's the complementary solution, okay? Now, it's time to make a guess for the Yp, right? If we look at blindly, this side, not homogeneous term. Then it suggests that, okay? It suggested that we make a guess for the Yp to be the undetermined coefficients times E-t. And plus from this one, undetermined coefficients B, right? That's the guess, right? But compared this our first guest is Yp, okay? Some constant terms, e-t, is a part of this complementary solution already, right? Then, okay, this guess is no good, right? Because this party is already a part of the complementary solution, okay? Then we have to modify it say, Ate-t + B, right? That's a right guess for the particular solution Yp, okay? If you're really plugging this form into that differential equation, then you can find it easily, okay? That, okay? The solution will be = -te- t+1, okay? In other words, A = -1, and B = +1, okay? You can find it. So this will be the particular solution, okay? What I'm saying is we need to remind, okay? How to modify the top of the particular solution. Whenever some part of our initial guess is a part of the complementary solution, okay? From this initial guess, we modify it to A*t*e-t, right? Okay, that's the point, okay? [MUSIC]