Now the solution here is to use the formula,

I2 is equal to R1, which is 300,

over the sum of the two, which is 6000,

times I sub s, which is 0.1, so

in this case, it's 0.05 amps.

And, I do want to point out, whenever the resistors are the same,

then the current is going to be divided equally between the two of them.

So if this is 0.1, then this 0.05 makes sense.

But what happens if R2 is say, 1000?

So I've reduced the resistance for R2 and left everything else the same.

Then I2 would be equal to 3000, again,

it's the opposite resistor over this sum,

which is now 4000, times 0.1,

the source, and that gives 0.075 amps.

So the current, actually, went up, so

the proportion that went to R2 got larger because the resistance went down, so

more currents are going to want to flow that direction.

Now I want you to recognize when to use the Current Divider Law.

In this particular case, it doesn't look like what we've been looking at,

because I've got this resistor here.

Well, that resistor doesn't really matter because its current source

tells me that the current is going this way.

And part of that current's going to split between this branch, and

part between this branch.

Now these two resistors are in parallel with one another, though they don't look

that way to be, physically, they don't look that way, but electrically, they are.

So the current is 0.6 going this way, and I can still use the Current Divider Law,

which gives me the opposite resistor for this branch.

The opposite resistor over the sum, times the current that goes into that node.